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Trying to understand operator overloading float ambiguous error

Jul 3, 2018 at 6:12pm
AL88 (146)
Hello I am trying to understand operator overloading and have written my own example.
When I try to compile it says the float is ambiguous. What does that mean I cant find anything on google. Thanks. 

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#include<iostream>
using namespace std;


class doSum
	{
		public:
	int sum (int a, int b)
	{ int c = a+b;
	return c;
	
	cout << "The answer is " << c << "\n";}
	
	float sum (float a ,float b)
	{
		float c;
		c = a+b;
		return c;
		cout << "The answer is " << c << "\n";}
	
	char sum (char a, char b)
	{
		char c = a + b;
		return c;
		cout << "The answer is " << c << "\n";
	}
	};

int main()
{
	
	
	
 doSum ints;
 ints.sum(7,8);
 doSum floats;
 floats.sum (6.7,7.8);
 doSum chars;
 chars.sum(64,99);

 
	}
Edit & run on cpp.sh
Jul 3, 2018 at 6:49pm
helios (17523)
When you call ints.sum(7,8) the compiler can't tell if you want to call the float version or the char version, since 7 and 8 are freely convertible to either type.
Jul 3, 2018 at 7:04pm
Hippogriff (727)
I would think ints.sum(7,8) is ok because int is overloaded.

The compiler thinks you are passing 2 doubles when you do this floats.sum (6.7,7.8) and so it can't decide between int and float. Change it to floats.sum (6.7f,7.8f);
https://stackoverflow.com/questions/30003519/using-float-gives-call-to-overloaded-function-is-ambiguous-error

You are never calling the char version (64 and 99 are ints first).

You can't put cout after the return statements, they will never be called.
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