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Why will this not work?

Sep 6, 2012 at 11:54am
JonasQuist (22)
one last problem then 
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if (result >= 0.5){
cout<<"you are too drunk to drive, you BAC is:"<<" "<<result<<endl;
cin.get();

}
else (result <0.5)
{cout << "you can drivee but be careful";
 }
 return 0;
}


will this work? also it cant compile because it says it expects a ";" before the {else
Sep 6, 2012 at 12:09pm
R0mai (730)
The else branch shouldn't have a condition.

Sep 6, 2012 at 12:12pm
JonasQuist (22)
Thank you :)
Sep 6, 2012 at 12:24pm
JonasQuist (22)
even with thecin.get()it still closes
Sep 6, 2012 at 12:48pm
R0mai (730)
Could you please post a preferably small, but compliable code which reproduces the problem?
Sep 6, 2012 at 2:28pm
JonasQuist (22)
if (result >= 0.5){
cout<<"you are too drunk to drive, you BAC is:"<<" "<<result<<endl;
cin.get();

}
else
{cout << "you can drive but be careful";
system(pause);
}

return 0;
}


this is the end of the program. so when i run the exe. and the result is bigger than or equal to 0.5 it works, but if its less than 0.5 it just close down.
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