What is mean of #name ?

Jan 20, 2017 at 7:29pm

I saw some codes using macro definition to define a function alais. But I don't understand why it put "#" before argument like this :

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#define RegisterTcpFlow(name) \
    RegisterFlow(#name, &name::Construct, eTcp); \

What does #name mean ?

Thanks in advance.

Jan 20, 2017 at 8:30pm

Peter87 (11189)

It will give you the name as a string.

RegisterTcpFlow(hello) will expand to RegisterFlow("hello", &hello::Construct, eTcp);

Jan 20, 2017 at 10:04pm

buddha87 (58)

Thank you for reply. So it means it will convert hello as a variable to a string which is the variable name. Correct ?

Jan 21, 2017 at 10:42am

Peter87 (11189)

You can pass almost anything as argument to a macro, not just variables.

#include <iostream>

#define STR(str) #str

int main()
{
	std::cout << STR(This will be turned into a string.\n\t123...);
}

This will be turned into a string.
	123...

Last edited on Jan 21, 2017 at 11:10am

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